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6p^2+11p+4=0
a = 6; b = 11; c = +4;
Δ = b2-4ac
Δ = 112-4·6·4
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-5}{2*6}=\frac{-16}{12} =-1+1/3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+5}{2*6}=\frac{-6}{12} =-1/2 $
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